diff --git a/00. Jeremy's IT LAB CCNA course.md b/00. Jeremy's IT LAB CCNA course.md
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--- a/00. Jeremy's IT LAB CCNA course.md	
+++ b/00. Jeremy's IT LAB CCNA course.md	
@@ -23,3 +23,4 @@ tags:
 [[Static Routing]]
 [[The Life of a Packet]]
 [[Subnetting (Part 1)]]
+[[Subnetting (Part 2)]]
diff --git a/14. Subnetting (Part 2).md b/14. Subnetting (Part 2).md
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+++ b/14. Subnetting (Part 2).md	
@@ -0,0 +1,201 @@
+---
+id: 1777871422-VTLQ
+aliases:
+  - Subnetting (Part 2)
+tags: []
+---
+
+# Subnetting (Part 2)
+
+## Question
+
+45 hosts -> SW1->+--+<-SW3<-45 hosts
+                 |R1|
+45 hosts -> SW2->+--+<-SW4<-45 hosts
+
+Divide the 192.168.1.0/24 network into four subnets that can accommodate 
+the number of hosts required.
+
+The first subnet (Subnet 1) is 192.168.1.0/26 What are the remaining subnet
+
+Hint: Find the broadcast address of Subnet 1. The next address is the network address of
+Subnet 2. Repeat the process for Subnets 3 and 4
+
+### Subnet 1
+
+Subnet 1: 192.168.1.0/26
+11000000.10101000.00000001.00**000000**
+   192  .   168  .   1     .   0
+broadcast address:
+11000000.10101000.00000001.00**111111**
+   192  .   168  .   1     .   63
+
+192.168.1.0 to 192.168.1.63
+
+### Subnet 2
+
+Subnet 2: 192.168.1.64/26
+11000000.10101000.00000001.01**000000**
+   192  .   168  .   1     .   64
+11000000.10101000.00000001.01**111111**
+   192  .   168  .   1     .   127
+
+192.168.1.63 to 192.168.1.127
+
+### Subnet 3
+
+Subnet 3: 192.168.1.128/26
+11000000.10101000.00000001.10**000000**
+   192  .   168  .   1     .   128
+11000000.10101000.00000001.10**111111**
+   192  .   168  .   1     .   191
+
+192.168.1.128 to 192.168.1.191
+
+### Subnet 4
+
+Subnet 4: 192.168.1.192/26
+11000000.10101000.00000001.11**000000**
+   192  .   168  .   1     .   192
+11000000.10101000.00000001.11**111111**
+   192  .   168  .   1     .   255
+
+192.168.1.192 to 192.168.1.255
+
+### Trick
+
+By adding 64 the last bit of the network portion you can find the network address
+
+## Subnetting
+
+11000000.10101000.00000001.0**0000000**
+192.168.255.0
+
+11000000.10101000.11111111.1**0000000**
+192.168.255.0
+Borrowing 1 bit = can make 2 subnets
+
+### Formulas
+
+2^x = number of subnets
+(x=number of 'borrowed' bits)
+
+2^n-2 = number of hosts
+(x=number of hosts bits)
+
+## Identify the subnet
+
+What subnet does host 192.168.5.57/27 belong to?
+
+11000000.10101000.00000101.00111001
+192.168.5.57
+
+The borrowed bits are
+11000000.10101000.00000101.**001**11001
+
+to find the network address we need to change the host bits by zero
+
+11000000.10101000.00000101.**001**00000
+192.168.5.32
+
+What subnet does host 192.168.29.219/29 belong to?
+
+11000000.10101000.00011101.**11011**011
+192.168.29.219
+
+to find the network address we need to change the host bits by zero
+11000000.10101000.00011101.**11011**000
+192.168.29.216
+
+## Subnets / hosts (class C)
+
+
+| Prefix Length | Number of subnets | Number of Hosts |
+| ------------- | ----------------- | --------------- |
+|      /25      |        2          |       126       |
+|      /26      |        4          |       62        |
+|      /27      |        8          |       30        |
+|      /28      |        16         |       14        |
+|      /29      |        32         |       6         |
+|      /30      |        64         |       2         |
+|      /31      |        128        |       0 (2)     |
+|      /32      |        156        |       0 (1)     |
+
+
+## Subenetting Class B
+
+The process of subnetting Class A, Class B and Class C networks is :
+Exactly the same !
+
+### Example 1
+
+You have been given the 172.16.0.0/16 network. You are asked to create 80
+subnets for your company's various LANs, What prefix length should you use ?
+
+172.16.0.0/16
+
+10101100.00010000.00000000.00000000
+  172   .   16   .   0    .   0    
+
+We have to borrow 7 bits  = 128 subnets
+
+10101100.00010000.**0000000**0.00000000
+  172   .   16   .   0    .   0    
+
+### Example 2
+
+You have been given the 172.22.0.0/16 network. You are asked to create 500
+subnets for your company's various LANs, What prefix length should you use ?
+
+172.22.0.0/16
+
+10101100.00010000.00000000.00000000
+  172   .   22   .   0    .   0    
+
+We have to borrow 9 bits  = 512 subnets = /25
+
+10101100.00010000.**00000000.0**0000000
+  172   .   22   .   0    .   0    
+
+### Example 3
+
+You have given the 172.18.0.0/16 network. Your company requires 250 subnets with the
+same number of hosts per subnet. What prefix length should you use
+
+172.18.0.0
+
+10101100.00010000.00000000.00000000
+  172   .   18   .   0    .   0    
+
+We have to borrow 8 bits  = 256 subnets = /24
+
+10101100.00010000.**00000000**.00000000
+  172   .   18   .   0    .   0    
+
+## Subnets / hosts (class B)
+
+
+| Prefix Length | Number of subnets | Number of Hosts |
+| ------------- | ----------------- | --------------- |
+|      /17      |        2          |     32766       |
+|      /18      |        4          |     16382       |
+|      /19      |        8          |      8190       |
+|      /20      |        16         |     4094        |
+|      /21      |        32         |     2044        |
+|      /22      |        64         |     1022        |
+|      /23      |        128        |       510       |
+|      /24      |        256        |       254       |
+|      /25      |        2          |       126       |
+|      /26      |        4          |       62        |
+|      /27      |        8          |       30        |
+|      /28      |        16         |       14        |
+|      /29      |        32         |       6         |
+|      /30      |        64         |       2         |
+|      /31      |        128        |       0 (2)     |
+|      /32      |        156        |       0 (1)     |
+
+
+## Review 
+
+- Subnetting practice questions (class C networks)
+- Subnetting Class B networks